### Solar Power

##
**Solar Power :-**

#### How Much Fuel Does It Takes To Power A Light bulb For A Year?

HOW MUCH ENERGY-WHETHER ELECTRIC,COAL,NUCLEAR, OR OTHERWISE-IS REQUIRED FOR A 100-WATT

LIGHTBULB TO RUN A YEAR, 24 HOURS A DAY?

(Kilowatt-hour(kWh)=unit of energy equal to 1.000 watt hours

a 100-watt light uses 0.1 kilowatt-hours worth of energy in

hour how much energy does an electric 100-watt lightbulb use

a year?0.1kW * 8,760hours in a year = 876 kWh)

### COAL :- 1.Burning 1ton Of Coal Creates 2,460kWh Of Energy.

2.876kWh/2,460kWh/ton=0.357 tons3.0.357tons = 714 pounds

NUCLEAR :- 1. 1pound of the uranium 235 isotope can produce 10,246,469kWh of energy.

2.876 kWh/10,246,469kWh/pound=8.5*10^-5pounds.

3.Divide this by .35(the average thermal efficiency of uranium 235 is only

35%) =2.4*106^-4 pounds.

4.Divide this by .007(uranium 235 isotope needed for nuclear fission makes up

only .7% of raw uranium) = .035 pounds of natural uranium.

1

### NUCLEAR GAS :- 1.1 pound of natural gas can produce 6.12 kWh of energy.

2.876kWh/6.12kWh/pound=143 pounds of natural gas.### WIND(1.5MW turbine operating at 25% capacity for 2hrs, 20 min 9sec.)

1. 1.5 megawatt turbine x 365 days x

24 hours x 25% capacity =3,285 mWh=3,285 kWh

2. 876kWh/3,285,000 kWh/year = 2,67x10^-4 years

3. 2.67x10^4 years = hours 20 minutes 9 seconds.

### SOLAR

(8 days 18 hrs 14 min 24sec.)on 100 square meters of solar panels1. Assuming a yield between 20-25% (average solar convertion efficiency),

a one sqaure meter solar panel can produce 1 kWh of energy in a day.

2. 100 one square meter panels producing 100kWh would

require 8 days 18 hours 14 minutes and 24 seconds.

### HYDROELECTRIC (339 kW turbine operating at 80% efficiency

for 2hrs and 35 min.with 500ft^3 of waterper second falling from 10 ft.)

1. The power of a hydro-electric turbine =(height of dam) x (river flow) x

(efficiency) /11.8 (converts unit of feet and seconds into kilowatts)

2.Assuming:dam height(10 feet) x river flow(500 ft^3 per second)

x (80% efficiency)/11.8=339kW turbine.

3. 876 kWh/339kW= 2hours and 35 minutes

Tags: Solar Power

Subscribe to:
Post Comments (Atom)

## Share your views...

0 Respones to "Solar Power"## Post a Comment